Question

the areas is two similar triangle are 81cm square and 49vm square respectively.if the altitude of the bigger triangle is 4.5 cm ,find the corresponding altitude of smaller triangle

Answer 1

The two triangles are similar. Let the triangles be ABC (bigger) and XYZ (smaller) . It means that ABC is similar to XYZ.

Therefore,
AB^2/XY^2 = Area of ABC/ Area of XYZ
AB^2/XY^2= 81/49
Square root both sides

AB/XY= 9/7

Now, the sides and altitudes of both the triangles will be in the ratio of 9/7.

Altitude of bigger/ Altitude of smaller= 9/7
4.5/Altitude of smaller= 9/7
Altitude of smaller= 4.5*7/9
Altitude of smaller = 3.5 cm !!!ANSWER!!!