the areas of 2 similar triangles ABC and DEF are 100cm sq and 144cm sq respectively.if EF=15 then find BC
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For this problem we use the theorm-Areas of similar triangles will be equal to square of corresponding sides.
Triangle ABC is similar to Triangle DEF (given)
Therefore
⇒ ar(Triangle ABC)/ar(Triangle DEF)=(BC/EF)²
⇒100/144=(BC/15)²
⇒100x15x15/144=BC²
⇒156.25=BC²
⇒√156.25=BC
⇒∴12.5 cm=BC
Hope this helps!
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