Question

the areas of 2 similar triangles are 169 cmsquare and 121cmsquare . if the longest side of the larger triangle is 26cm , then find the longest side of the other triangle​

Answer 1

Let the sides be AB and PR

(AB/PR)² = ar(∆ABC)/ar(∆PQR)

(26/PR)² = (13/11)²

PR = 26 x 11/12

PR= 22cm

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Answer 2

Say bigger triangle ABC is similar to the small one EFG . AS we know that if two triangle are similar the ratio of the area of the 2 triangle is equal to the square of their corresponding sides. JUST THE SE I HAVE DONE HERE. I have highlighted them

TRY TO UNDERSTAND. THANKS

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