The areas of pistons in a hydraulic machine are 10 cm2 and 40 cm2 . What force on the smaller piston will support a load of 1000 N on the larger piston?
Answers
The force required to support the load is 250N
Area of small piston = A1 = 10cm²
Area of wider piston = A2 = 40cm²
Let the force on small piston be = F1
Force on wider piston = 1000 N
According to the principle of hydraulic machine -
Pressure on the small piston = Pressure on the wider piston
= F1/A1 = F2/A2
= F1/ 10 = 1000/40
F1 = 1000/40.10
F1 = 250
Thus, the force required to support is 250N.
Answer:
250N
Explanation:
Area of small piston = A1 = 10cm²
Area of wider piston = A2 = 40cm²
Let the force on small piston be = F1
Force on wider piston = 1000 N
According to the principle of hydraulic machine -
Pressure on the small piston = Pressure on the wider piston
= F1/A1 = F2/A2
= F1/ 10 = 1000/40
F1 = 1000/40.10
F1 = 250
Thus, the force required to support is 250N.