Question

The areas of pistons in a hydraulic machine are 5 cm and 625 cm . What force on the smaller piston will support a load of 1250 N on the larger piston? State any assumption which you make in your calculation.

Answer 1

Explanation:

Answer:

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$a1 = 5cm \: and \: a2 = 625cm$

$f = 1250$

By using Formula of hydraulic machine

$\frac{f1}{f2} = \frac{a1}{a2}$

put the given values :

$\frac{f1}{1250} = \frac{5}{625}$

$\frac{f1}{1250} = \frac{1}{125}$

$f1 = \frac{1250}{125} = 10newton$

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