The Areas Of Pistons In A Hydraulic Machine Are 5 Cm Square And 625 M Square . What Force On The Smaller Piston Will Support A Load Of 1250N On The Larger Piston? State Any Assumption Which You Make In Your Calculation
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Explanation:
Force/Area remains constant => Pascal's Law
A1= 5 sq.cm. = 5/100×100 sq.m.=0.0005 sq.m.
A2=625 sq.m.
F1=1250 N
F2=?
F1/A1 = F2/A2 => 1250/625 = F2/0.0005
=>F2 =2×0.0005 =0.001 N. Hope it helps you.
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