Question

The areas of the parallelogram determine by A=2i+j+3k and B=12j-2k is approximately

Answer 1

Answer:

0

Explanation:

a=2i+j+3k

b=12j-2k

area of parallelogram=|a×b|

| i j k|

| 2 1 3|

| 0 12 -2|

=2(_2-36) -1(-4-0)+3(24-0)

= -76+4+72

=O