Math, asked by dhanushDhanush9677, 1 year ago

The areas of the rectangle and square are in the ratio 3:2. If the length of the rectangle is doubled and the side of the square is tripled, find the ratios of the new areas

Answers

Answered by siliverisrinivas
0
the ratio of second rectangle is 3:2
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Answered by SmãrtyMohït
13
Here is your solution


We know that Area of rectangle = length * breadth

We know that Area of square = a^2.

Now,

Given that ratio of area of rectangle and area of square is 3:2.

= > (lb)/(a^2) = 3/2. ------ (1)

(i)

Given that length of rectangle is doubled = 2l.

Area = (2l)(b) = 2lb.

(ii)

Given that Side of square is tripled = 3a.

Area of square = (3a)^2 = 9a^2.

Now,

Ratio of areas:

= > (2lb)/9a^2

= > (2/9) * (lb/a^2)

= > (2/9) * (3/2) {From (i)}

= > 1/3

= > 1 : 3

hope it helps you
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