The areas of three adjacent faces of a cuboid are x, y, and z. If the volume is V, prove that V2 = xyz.
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Answered by
1
Step-by-step explanation:
V = l×b×h
area of 3 adjacent faces=lb×bh×lh
=l×l×b×b×h×h
which is equal to square of V
Answered by
24
Answer:
v² = xyz
Step-by-step explanation:
we assume that the dimensions of cuboid are l, b, h as for length, breadth and height
according to the question,
area of three faces x, y and z
l × b = x--(1)
b × h = y---(2)
l × h = z---(3)
on multiplying (1 ),(2) and (3) we have
lb × bh × lh = xyz
l²×b²×h² = xyz
(lbh)² = xyz
∴ v² = xyz (∵ volume of the cuboid= v = lbh)
hope it helps!
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