The areas of two similar Δ are 121 cm² and 64cm².If median of first Δ is 12.1cm. Find the
median of second Δ.
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Answer:
The ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding medians. Therefore,
121/64 = (12.1)²/x² , Where x is the Median of the other △.
=> x² = (12.1)²/x² × 64 / 121 => x = √121/100 × 64
= 11/10 × 8 = 8.8 Cm.
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