Question

The areas of two similar triangle are 72 cm² and 242 cm² find the ratio of their corresponding sides (for 1 marks )

Answer 1

LET TRIANGLE ABC AND DEF ARE TWO SIMILAR TRIANGLE.

AREA OF TRIANGLE ABC=72 CM²

AREA OF TRIANGLE DEF = 242 CM²

WE KNOW THAT,

RATIO OF AREA OF SIMILAR TRIANGLE = SQUARE OF THE CORRESPONDING SIDES .

AR(ABC)/AR(DEF) = (AB/BC)²

72/242 = AB²/BC²

AB²/BC²= 36/121

AB/BC = ✓36/✓121

Therefore,

AB/BC = 6/11

HENCE,

THE RATIO OF THE CORRESPONDING SIDES OF THE TRIANGLE = 6/11

Answer 2

let area of 1st triangle be 72cm^2 and 2nd triangle be 242 cm^2
area of 1st triangle/area of 2nd triangle=(side of 1st triangle)^2/(side of 2nd triangle)^2
72/242=(side of 1st triangle)^2/(side of 2nd triangle)^2
side of 1st triangle/side of 2nd triangle=6√2/11√2
=6/11