the areas of two similar triangles ∆ABC~∆DEF are 49cm2 and 144cm2 if BC=7cm find EF
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Step-by-step explanation:
Given :∆ABC ~ ∆ DEF
ar(∆ABC) = 49cm2
ar(∆DEF) = 144cm2
BC= 7 cm
To find : EF
Solution :
ar(∆ABC)/ar(∆DEF) =BC^2/EF^2
49cm2/144cm2= (7)^2/ EF^2
49*EF^2= 144*49
EF^2= 144*49/49
EF^2= 144
EF= 12 cm ____
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