Question

The areas of two similar triangles are 100 cm^2 and 49 cm^2 respectively . If the median of the bigger triangles is 5 cm, find the corresponding median of the other triangle

Answer 1

Answer:

As we know that, for two similar triangles

(Area)₁/(Area)₂ = (side)₁²/(side)₂²

(Area)₁ = 100 cm²

(Area)₂ = 49 cm²

(altitude)₁ = 5 cm

(altitude)₂ = x

100/49 = (5)²/x²

⇒x² = [(25)×49]/100

⇒x = (5×7)/10

=3.5 cm

Answer 2

Answer:3.5 cmStep-by-step explanation:We are given that The areas of two similar triangles are 100 cm and 49 cm respectively .We are also given that The altitude of the bigger triangles is 5 cmLet the altitude of smaller triangle be xTheorem : The ratio of area of similar triangles is equal to the ratio of squares of corresponding altitudesSo,

Hence the corresponding altitude of other triangle is 3.5 cm