Question

The areas of two similar triangles are 100 cm2 and 40 cm2 resp.if the altitude of the bigger triangle is 5 cm find the corresponding altitudes of the smaller one

Answer 1

smaller side is equal to √10

Answer 2

GIVEN:-

b=12cm

area=${48cm^2}$

TO FIND:-

h=?

solution:-

WE KNOW THE AREA OF TRIANGLE AS

$= > \frac{1}{2} \times b \times h$

now, put the given values.....

$\frac{1}{2} \times 12 \times h = {48cm}^{2}$

$= > \frac{1}{ \cancel2} \times \cancel{12} \times h = 48$

$= > 6 \times h = 48$

$= > h = \frac{ \cancel{48}}{ \cancel 6}$

$= > h = 8cm$

so, the height is

$\boxed{8cm}$