Question

The areas of two similar triangles are 121cm² and 64 cm² respectively . if the altitude of the first triangle is 12.1 cm , then the corresponding altitude of the other triangle is


pls help me​

Answer 1

Answer:

The ratio of the areas of two similar triangles is equal to the ratio of the squares of the corresponding medians. Therefore,

64

121

=

x

2

(12.1)

2

, where x is the median of the other △.

⇒ x

2

=

121

(12.1)

2

×64

⇒x=

100

121

×64

=

10

11

×8=8.8 cm.

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