Question

The areas of two similar triangles are 12cm sq and 48 cm sq . if the height of the similar one is 2.1 cm , then the corresponding height of the bigger one is

Answer 1

Hey there!

Given,

Area of two similar triangles = 12 cm² , 48 cm² .

Area of bigger triangle = 48 cm²

Area of smaller triangle = 12 cm²

We know that, Ratio of the areas of two similar is equal to square of the ratio of corresponding heights or altitudes.

Given, Height of smaller triangle =2.1 cm.

$\boxed{\frac{ Ar(Bigger \: triangle)}{Ar(Smaller \: triangle)} = ( \frac{ Height \: of \: bigger \: triangle } {Height \: of \: smaller \: triangle } )^2}$

$\implies \frac{ 48}{12} = \frac{(Height \: of \: bigger \: triangle)^2 } { 2.1^{2}}$

4 = (Height of the triangle)² / 4.41

√(4 * 4.41) = Height of the bigger triangle

Height of the bigger triangle = 2 * 2.1 = 4.2 cm.

Hope helped!

Answer 2

Answer:

4.2cm

Step-by-step explanation: