Question

The areas of two similar triangles are 16 cm² and 25 cm² respectively. If the difference of their corresponding altitudes is 10 cm, find the lengths of altitudes.

Answer 1

Here is your solution :

We know,  Ar.(triangle1)/Ar.(triangle2) = Sq. of ratio of corresponding sides

Let the ratio be x:y

Then,

x^2/Y^2 = 16/25

(x/y)^2 = 16/25

x/y = 4/5.

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Answer 2

Answer:

Step-by-step explanation:

Area(triangle1)/Area(triangle2) = Square of ratio of the corresponding sides

Let the ratio be x:y

Then,

x2/Y2 = 16/25

(x/y)2 = 16/25

x/y = under root 16/25

X/y = 4/5