Math, asked by pavelshchienko, 1 year ago

The areas of two similar triangles are 16 cm2 and 25 cm2. One of the sides of the first triangles is 2 cm. What is the length of the corresponding side of the other triangle?

Answers

Answered by bansil003
1

HOPE IT HELPS YOU.☺☺

Attachments:

pavelshchienko: thank you so much!
bansil003: ☺ ☺
Answered by wifilethbridge
5

The length of the corresponding side of the other triangle is 2.5

Step-by-step explanation:

The areas of two similar triangles are 16 sq.cm. and 25 sq.cm.

One side of first triangle = 2 cm

Theorem : The ratio of the area of two similar triangles is equal to the ratio of the corresponding of the sides of similar triangles

So, \frac{16}{25}=\frac{2^2}{x^2}

x=\sqrt{\frac{2^2 \times 25}{16}}

x=2.5

Hence the length of the corresponding side of the other triangle is 2.5

#Learn more:

The areas of two similar triangles are 100 cm2 and 64 cm2. if the median of greater side of first triangle is 13 cm, find the corresponding median of the other triangle ?

https://brainly.in/question/3064902

Similar questions