Question

The areas of two similar triangles are 169 sq.cm and 144 sq.cm respectively. If the
altitude of smaller triangle is 24 cm then find the corresponding altitude of larger triangle ?

plz help me for this question
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Answer 1

Answer:

altitude= 26 cm

Step-by-step explanation:

since , by theorem ,

(area of larger ∆ / area of smaller ∆ )

=( altitude of larger ∆ /altitude of smaller∆) ^2

therefore, (169/144)=(h/24)^2

h/24 = √(169/144)

h/24 = 13/12

h= 13*24/12

h= 13*2 =26cm

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