Question

The areas of two similar triangles are 18 cm2 and 8 cm2. One of the sides of the first triangle is 4.5 cm. What is the length of the corresponding side of the other triangle?

Answer 1

let,
the similar triangles are ABC and DEF
We know that similar sides of similar triangles are corresponding.
So,
Area of triangle ABC/Area of triangle DEF=AB/DE
18/8=4.5/DE
9/4=9/2/DE
9/4 =9/2DE
18DE=36
DE=36/18
=2
So,the length of the corresponding side of the other triangle is 2cm

Answer 2

The corresponding length of the other triangle is 4.5 cm.

Step-by-step explanation:

Given:

The areas of two similar triangles are 18 cm^2 and 8 cm^2. One of the sides of the first triangle is 4.5 cm. What is the length of the corresponding side of the other triangle

Solution:

Ratio of areas = 18 : 8; 9 : 4

Ratio of length is the square root of ratio, which is 3 : 2

Given the side of first triangle is 4.5 cm, multiply that by $\frac{2}{3}$,  the corresponding length is 3 cm.

To know more:

If the altitudes of a triangle are in the ratio 2 : 3 : 4, then the lengths of the corresponding sides are in the ratio

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