The areas of two similar triangles are 25 cm2 and 36cm2 respectively.if the altitude of the first triangle is 2.4cm,find the corresponding altitude of the other
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Answered by
35
As we know that, for two similar triangles
(Area)₁/(Area)₂ = (side)₁²/(side)₂²
(Area)₁ = 25 cm²
(Area)₂ = 36 cm²
(altitude)₁ = 2.4 cm
(altitude)₂ = x
25/36 = (2.4)²/x²
⇒x² = [(5.76)×36]/25
⇒x = (2.4×6)/5
=2.88 cm
(Area)₁/(Area)₂ = (side)₁²/(side)₂²
(Area)₁ = 25 cm²
(Area)₂ = 36 cm²
(altitude)₁ = 2.4 cm
(altitude)₂ = x
25/36 = (2.4)²/x²
⇒x² = [(5.76)×36]/25
⇒x = (2.4×6)/5
=2.88 cm
Answered by
3
Answer:
2.88 cm
Step-by-step explanation:
Property : In two similar triangles, the ratio of their areas is the square of the ratio of their sides. and also In Similar Triangles - ratios of parts, the perimeter, sides, altitudes and medians are all in the same ratio.
Let the altitude of second triangle be x
So,
Hence the corresponding altitude of the other is 2.88 cm
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