Question

the areas of two similar triangles are 81 cm square and 49 CM square respectively if the altitude of bigger triangle is 4.5 cm find the corresponding attitude of the smaller triangles​

Answer 1

Answer:

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Answer 2

Answer:

let the two triangles be ABC and PQR and altitudes be BX(bigger) and QY(smaller)

ar(ABC)/ar(PQR) = 49/81........1

we know that ar(ABC)/ar(PQR) = BXsquare/QYsquare

ar (ABC)/ar (PQR) = (4.5/QY)square..........2

from 1 and 2

(4.5/QY)square = 49/81

(4.5/QY)square = (7/9)square

4.5/QY = 7/9

QY = 14/81

= 0.56 (approx)