Question

the areas of two similar triangles are 81 cm square and 49 CM square respectively if the altitude of the bigger triangle is 4.5 cm find the corresponding altitude of the smaller Triangle​

Answer 1

Answer:

3.5 cm

Step-by-step explanation:

81:49

81/49

9^2/7^2

therefore ratio = 9:7

bigger triangle

altitude = 4.5/9~ X /7

= 0.5*7 = X

= 3.5

therefore median of the second triangle is 3.5 cm