Question

The areas of two similar triangles are 81 cm² and 49 cm respectively. If an altitudes of the
smaller triangle is 3.5 cm, then the corresponding altitude of the bigger triangle is
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Answer 1

Answer:

We have, ΔABC ~ ΔPQR Area (ΔABC) = 81 cm2, Area (ΔPQR) = 49 cm2 And AD and PS are the altitudes By area of similar triangle theorem Since, the ratio of the area of two similar triangles is equal to the ratio of the squares of the squares of their corresponding altitudes and is also equal to the squares of their corresponding medians. Hence, ratio of altitudes = Ratio of medians = 9 : 7Read more on Sarthaks.com - https://www.sarthaks.com/33691/the-areas-of-two-similar-triangles-are-81-cm-2-and-49-cm-2-respectively

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Explanation:

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