Question

The areas of two similar triangles are 81 cm2 and 49 cm2 respectively. If the altitude of the first triangle is 6.3 cm, find the corresponding altitude of the other.

Answer 1

Answer:

Length of the corresponding Altitude is =4.9cm

Answer 2

GIVEN:-

b=12cm

area=${48cm^2}$

TO FIND:-

h=?

solution:-

WE KNOW THE AREA OF TRIANGLE AS

$= > \frac{1}{2} \times b \times h$

now, put the given values.....

$\frac{1}{2} \times 12 \times h = {48cm}^{2}$

$= > \frac{1}{ \cancel2} \times \cancel{12} \times h = 48$

$= > 6 \times h = 48$

$= > h = \frac{ \cancel{48}}{ \cancel 6}$

$= > h = 8cm$

so, the height is

$\boxed{8cm}$