The areas of two similar triangles are 81cm & 49cm respectively. Find the ratio of the corresponding medians.
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Given : ΔABC ~ ΔPQR
Area (ΔABC) = 81 cm2
Area (ΔPQR) = 49 cm2
Figure:
And AD and PS are the altitudes
By area of similar triangle theorem: The ratio of the areas of two similar triangles equal to the ratio of squares of the corresponding sides of triangles.
We also know that:
So, Ratio of altitudes = 9/7
Hence, ratio of altitudes = Ratio of medians = 9:7
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