The areas of two similar triangles are 9 cm2 and 16 cm2respectively . The ratio of their corresponding sides is:
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As the area can found by this so if you take under root of area it will be 3/4
√9/√16=3/4
by above theorem
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Given:
The areas of two similar triangles are 9 cm² and 16 cm².
We need to find the ratio of the corresponding sides.
Since we know that the two given triangles are similar to each other, we know that the ratio of their areas is the square of the ratio of the corresponding sides.
Therefore, we get
ar(tri 1)/ar(tri 2) = (side1)/(side2)=19/16
Thus, we finally get
side 1/side 2 = 3/4.
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