Math, asked by krishna7349, 5 months ago

The areas of two similar triangles are in respectively 9 cm2 and 16 cm2. The ratio of their corresponding sides is
(a) 2 : 3                                   (b) 3 : 4                   (c) 4 : 3                          (d) 4 : 5​

Answers

Answered by uhhhhhh
3

Answer:

b) 3:4

Step-by-step explanation:

root over 9:16 is 3:4

Answered by sankar3011
0

Answer:

3:4

Step-by-step explanation:

By formula,

Area of ABC/Area of PQR = Length of side A ^2/Length of side B^2

9/16 = x/y

On squaring both sides we get,

3/4 = x/y

On equating we get

x = 3 and y = 4

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