Math, asked by BrainlyHelper, 1 year ago

The areas of two similar triangles are in respectively 9  cm^{2} and 16  cm^{2} . The ratio of their corresponding sides is
(a) 3 : 4
(b) 4 : 3
(c) 2 : 3
(d) 4 : 5

Answers

Answered by nikitasingh79
2

Answer:

The ratio of their corresponding sides is 3 : 4.

Among the given options option (a) 3 : 4 is the correct answer.

Step-by-step explanation:

Given:

Areas of two similar triangles are 9 cm² & 16 cm²

We know that the ratio of areas of two similar triangles is equal to the ratio of squares of any two corresponding sides.

ar(∆1/)ar(∆2) = (side1/ side 2)²

9/16 = (side1/ side 2)²

√9/16 = (side1/ side 2)

¾ = (side1/ side 2)

side1 :  side 2 = 3 : 4  

Hence, the ratio of their corresponding sides is 3 : 4.

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Answered by Anonymous
13

\huge\bold\pink{SOLUTION:-}

•Areas of two similar triangles are 9 cm² & 16 cm²

Also, the ratio of areas of two similar triangles is equal to the ratio of squares of any two corresponding sides.

ar(∆1/)ar(∆2) = (side1/ side 2)²

9/16 = (side1/ side 2)²

√9/16 = (side1/ side 2)

¾ = (side1/ side 2)

side1 :  side 2 = 3 : 4  

\huge\underline\mathfrak{Answer:-}

Hence, the ratio of their corresponding sides is 3 : 4.

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