Question

The areas of two similar triangles are In the ratio of 64:49 Then it's corresponding ratio of sides is

Answer 1

Answer:

$\frac{ab}{de} = \frac{ac}{df} = \frac{bc}{ef} = \sqrt{ \frac{64}{49} } = \frac{8}{7} .$

Step-by-step explanation:

$let \: the \: two \: triangles \: be \: abc \: \: \: and \: \: \: def \\ \\ then \: \: \: \frac{area \: (abc)}{area(def)} = \frac{64}{49} = \frac{ {(side \: of \: triangle \: abc)}^{2} }{ {(side \: of \: triangle \: def)}^{2} } \\ \\ \frac{ab}{de} = \frac{ac}{df} = \frac{bc}{ef} = \sqrt{ \frac{64}{49} } = \frac{8}{7} .$