Question

the areas of two similar triangles are respectively 9cm2 and 16cm2. then ratio of the corresponding sides are​

Answer 1

Solution :-

Given : The areas of two similar triangles are respectively 9 cm² and 16 cm².

Suppose that ar(△ABC) = 9 cm²

ar(△PQR) = 16 cm²

To find : Ratio of their corresponding sides i.e., BC and QR

ar(△ABC)/ar(△PQR) = BC²/QR² [By theorem]

=> 9/16 = BC²/QR²

=> 3²/4² = BC²/QR²

=> 3/4 = BC/QR

Hence,

Ratio of their corresponding sides = 3 : 4

Answer 2

Answer:

To find squares painting sides of ratio example BC and QR .

Area ( And ) / At ( PQR) = bc^ 2 / QR ^2

9/16 = BC^2 / QR ^ 2

3^2/4^2 = Bc^2 / QR ^2

3/4 = BC /QR

So , BC / QR = 3:4.

So Answer is 3:4 .

✓It is in short method.

Thanks .