Question

the areas of two similar triangles are respectively 9cm² and 16cm² the ratio of the corresponding sides are

Answer 1

1st let tri.ABC nd tri.DEF such that ar. of tri.ABC=9cm sq. nd ar. of tri.DEF=16cm sq. we know that the ratio of area of two triangles is equal to the ratio of squares of the corresponding sides.. ar(tri.ABC)/tri.(tri.DEF)=AC sq/DF sq =>9/16=AC sq/DF sq => 3/4 =AC/DF....

ratio is 3:4

hope it helps you

Answer 2

Answer:

The Answer is 3:4