Question

the areas of two similar triangles triangle ABC and triangle pqr 64 CM square and 169 cm square if AC 6.9 CM then PR would be Dash ​

Answer 1

Answer:

by the relation of similar triangles

we conclude that,

$\frac{ {ac}^{2} }{ {pr}^{2} } = \frac{64}{169 } \\ \frac{ac}{pr} = \frac{8}{13} \\ as \: a c \: is \: 6.9 \: put \: the \: value \\ \frac{6.9}{pr} = \frac{8}{13}$

so pr is equal to 11.2125cm

hope this will help you..

Answer 2

Answer:

11.2cm

Step-by-step explanation:

ΔABC SIMILAR TO ΔPQR

A(ΔABC)÷A(PQR)=64÷169

ALSO, A(ΔABC)÷A(PQR)= AC²÷PR²

THUS AC²÷PR²=64÷169

            AC÷PR=8÷13.......(TAKING SQUARE ROOT ON BOTH SIDES)

           13(AC)=PR(8)

           PR=13×AC÷8

   =13×6.9÷8

=89.7÷8

=11.2cm