Question

The areas of two similar trianglesare81cm and 49cm respectively. If the attitude bigger triangle is 4.5cm . Find the corresponding altitude of the smaller triangle.

Answer 1

Answer:

3.5

Step-by-step explanation:

given:ar∆ABC=81cm²

ar∆PQR=49cm²

∆ABC~∆PQR

altitude AD=4.5cm

to find:PS

solution:since ∆ABC~∆PQR

therefore ∆ABC/∆PQR=(AD/PS)²

81/49=(4.5/PS)²

(9/7)²=(4.5/PS)²

9/7=4.5/PS

PS=4.5*7/9=3.5cm