The ares of an iscoceles triangle is 60 cm s.q and the length of each one its equal sides is 13 cm. Find its base ?
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Answers
Answered by
6
Answer:
b≈10cm
or
24cm
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24cm. but how
Answered by
4
HEYA
HERE'S UR ANSWER
So A = 60cm²
AB=BC=13cm
A=1/2 b*h
So currently we only have the area but no height or base, so what you want to do is express height in terms of base.
So using Pythagoras :
a² = b² + c²
13² = h² + (1/2 b)²
h² = 169 - 1/4 b²
h = √(169 - 1/4 b²)
Back to area:
60 = 1/2 b √(169 - 1/4 b²)
We now solve for b:
120 = b√(169 - 1/4 b²)
14,400 = b²(169 - 1/4 b²)
1/4 b⁴ − 169b² + 14,400 = 0
b⁴ - 676b² + 57,600 = 0
(b + 24)(b + 10)(b - 10)(b - 24) = 0
So b = ± 10, 24
However, since this is geometric, we can’t get a negative length so b can either be 10 or 24 cm.
HOPE IT HELPS
MARK ME BRAINLIEST PLZZZ
HERE'S UR ANSWER
So A = 60cm²
AB=BC=13cm
A=1/2 b*h
So currently we only have the area but no height or base, so what you want to do is express height in terms of base.
So using Pythagoras :
a² = b² + c²
13² = h² + (1/2 b)²
h² = 169 - 1/4 b²
h = √(169 - 1/4 b²)
Back to area:
60 = 1/2 b √(169 - 1/4 b²)
We now solve for b:
120 = b√(169 - 1/4 b²)
14,400 = b²(169 - 1/4 b²)
1/4 b⁴ − 169b² + 14,400 = 0
b⁴ - 676b² + 57,600 = 0
(b + 24)(b + 10)(b - 10)(b - 24) = 0
So b = ± 10, 24
However, since this is geometric, we can’t get a negative length so b can either be 10 or 24 cm.
HOPE IT HELPS
MARK ME BRAINLIEST PLZZZ
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