Question

the arethemetic mean of following attribute
is 50 find x
class0-20,20-40,40-60,60-80,80-
100
frequency 17,x,32,24,19​

Answer 1

Answer:

Step-by-step explanation:

N=∑f  

i

​  

=120                [Given]

⇒68+f  

1

​  

+f  

2

​  

=120

⇒f  

1

​  

+f  

2

​  

=52

Now,

Mean = 50  

⇒A+h[  

N

1

​  

∑f  

i

​  

u  

i

​  

]=50

⇒50+20×[  

120

4−f  

1

​  

+f  

2

​  

 

​  

]=50

⇒  

6

4−f  

1

​  

+f  

2

​  

 

​  

=0

⇒4−f  

1

​  

+f  

2

​  

=0

⇒f  

1

​  

−f  

2

​  

=4

Solving equations (i) and (ii), we get f  

1

​  

 = 28 and f  

2

​  

=24.