The argument of -2+2√3i
Answers
Answered by
3
z = -2 + 2√3i
arg(z) = tan-¹|y|/|x| + 2kπ where, k belongs to integers
here , y = 2√3
x = -2
arg(z) = principal value of tan-¹(√3) + 2kπ
We know,
When, x < 0 and y > 0 then principal value = π - tan-¹(y/x)
= π - tan-¹(√3)
= π - π/3 = 2π/3
hence,
arg(z) = 2π/3 + 2kπ , where k€I
arg(z) = tan-¹|y|/|x| + 2kπ where, k belongs to integers
here , y = 2√3
x = -2
arg(z) = principal value of tan-¹(√3) + 2kπ
We know,
When, x < 0 and y > 0 then principal value = π - tan-¹(y/x)
= π - tan-¹(√3)
= π - π/3 = 2π/3
hence,
arg(z) = 2π/3 + 2kπ , where k€I
Studious13chetan:
thanks a lot abhi.178
Answered by
3
COMPLEXITIES RESOLVED
Attachments:
thanx a lot bro
Similar questions