the argument of √3 +i is
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Answer:
Correct option is
C
65π
Given, z=−3+i
We have ∣z∣=32+12=2
Therefore, cosθ=2−3
and sinθ=21
Hence, θ=65π
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Given
The Argument of √(3) + i
Now
Where x = √(3) and y = 1
Its lie on 1st Quadrant
Argument of Z
θ = Tan⁻¹(y/x)
θ = Tan⁻¹(1/√3)
θ = π/6
There are two type of type of Argument
i)principal Argument
Amp(z) = π/6
ii)General Value of Argument
Arg(z) = π/6 + 2kπ
More information
Properties of Argument
arg(Z₁.Z₂)=arg(Z₁)+arg(Z₂) + 2kπ
arg(Z₁/Z₂)= arg(Z₁)-arg(Z₂) + 2kπ
arg(Zⁿ)=n.arg(Z₂) + 2kπ
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