Question

The argument of z=i+ (2 + 3i) 2​

Answer 1

Step-by-step explanation:

z=−3+i

Modulus

∣z∣=(−3)2+12

=3+1

=2

∣z∣=2

Argument

θ=tan−1ab

=tan−1−31

=−30

∴θ=180−30=150

θ=150×180π

θ=65π