Question

The arithmatic mean of a frequency distribution table is 8.1 . fixi = 132 + 5k and fi = 20 then k = ?​

Answer 1

Answer:

use formula,

\overline{x}=\frac{f_ix_i}{f}

x

=

f

f

i

x

i

where \overline{x}

x

is the mean , f is number of data values .

here given,

\overline{x}=8.1

x

=8.1

f_ix_i=132+5kf

i

x

i

=132+5k

and f=20f=20

so, 8.1 = (132 + 5k)/20

8.1 × 20 = 132 + 5k

162 = 132 + 5k

162 - 132 = 5k

30 = 5k

k = 6

hence, k = 6

Answer 2

Step-by-step explanation:

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