the Arithmetic mean of 30 students is 42. among them two got zero marks, then arthimetic mean of remaining students is
Answers
Answered by
15
According to question,
(a1 + a2 +.... a30) / 30 = 42
=> a1 + a2 +.... + a30 = 1260
Now,
a29 = a30 = 0
=> a1 + a2 +..... + a28 = 1260
=> (a1 + a2 +..... + a28) / 28 = 1260 / 28
=> Mean of remaining students = 45
(a1 + a2 +.... a30) / 30 = 42
=> a1 + a2 +.... + a30 = 1260
Now,
a29 = a30 = 0
=> a1 + a2 +..... + a28 = 1260
=> (a1 + a2 +..... + a28) / 28 = 1260 / 28
=> Mean of remaining students = 45
Lalithesh62:
Thank you
Answered by
4
According to question,
(a1 + a2 +.... a30) / 30 = 42
=> a1 + a2 +.... + a30 = 1260
Now,
a29 = a30 = 0
=> a1 + a2 +..... + a28 = 1260
=> (a1 + a2 +..... + a28) / 28 = 1260 / 28
=> Mean of remaining students = 45
Similar questions