The arithmetic mean of the following distribution is 50.
Class 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency 16 p 30 32 14
Find the value of p.
Answers
Answered by
3
Step-by-step explanation:
Given the frequency distribution and arithmetic mean is 50
We know arithmetic mean =
No of observations(observation)
sum of observations
=
∑f
∑fx
Now we can prepare table for calculating mean
class frequency (f) mid point of class (x) fx
0−10 16 5 80
10−20 P 15 15P
20−30 30 25 750
30−40 32 35 1120
40−50 14 45 630
Here ∑f=92+P
∑fx=2580+15P
Given mean =50
∴ arithmetic mean
x
ˉ
)=
∑f
∑fx
50=
92+P
2580+15P
2580+15P=50(92+P)
=4600+50P
15P−50P=4600−2580
−35P=2020
P=−
35
2020
=−57.7
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Answered by
3
Answer:
correct answer is 28 a+ fixi
fi
given
a= 50/2
= 25
25 =2580+15p
92+p
25(92+p)= 2580+15p
2300+25p= 2580+15p
10p =280
p = 280
10
= 28
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