Question

The arithmetic mean of two numbers is 34 and their geometric mean is 16 find numbers

Answer 1

let the no be x and y 
$\frac{x+y}{2}$ = 34.
x+y=68

xy=16*16=256
x(68-x)=256
$x^{2}$-68x+256=0
solving both
x=4 y=64

Answer 2

Answer:

Step-by-step explanation:

AM=A+B/2=34,A+B=68. ;(2×34) GM=sqrt(AB)=16,AB=256.(1) ;(16×16) B=68-A PUT IN (1), A(68-A)=256 by solving it we get eqn. [68A- A^A-256] On solving it we get A=64