Question

the arithmetic mean of x,x+3 x+6,x+9 and x+12 is 10 than find x 1. 1 2. 2 3. 6 4. 4​

Answer 1

Step-by-step explanation:

-by-step explanation:

\begin{gathered}Given \: observations \:are \:\\x,x+3,x+6,x+9 \: and \: x+12 \: is \: 10\end{gathered}

Givenobservationsare

x,x+3,x+6,x+9andx+12is10

\boxed {Mean(x)=\frac{Sum\:of\: observations}{Number \: of \: observations}}

Mean(x)=

Numberofobservations

Sumofobservations

Mean=10Mean=10

\implies \frac{x+x+3++x+6+x+9+x+12}{5}=10⟹

5

x+x+3++x+6+x+9+x+12

=10

\implies \frac{5x+30}{5}=10⟹

5

5x+30

=10

\implies \frac{5(x+6)}{5}=10⟹

5

5(x+6)

=10

\implies x+6=10⟹x+6=10

\implies x = 10-6⟹x=10−6

\implies x = 4⟹x=4

Therefore,

Value \:of\: x = 4Valueofx=4

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Answer 2

Answer:

x+6

Step-by-step explanation:

By definition,

Average=

5

x+(x+3)+(x+6)+(x+9)+(x+12)

5

5