Question

The arithmetic sequence is 71,68, 65
Is 0 a term of the sequence

Answer 1

Step-by-step explanation:

Given:The arithmetic sequence is 71,68, 65

Is 0 a term of the sequence

To find:Is 0 a term of this A.P.

Solution:

71,68, 65,...

here

a=71

d=68-71=-3

formula of nth term

$a_n = a + (n - 1)d$

put the value

$0 = 71 + (n - 1)( - 3) \\ \\ - 71 = - 3(n - 1) \\ \\ \frac{71}{3} = n - 1 \\ \\ n = \frac{71}{3} + 1 \\ \\ n = \frac{71 + 3}{3} \\ \\ \bold{n = \frac{74}{3}}\neq\:positive\:integer$

not divisible by 3 completely.

Number of terms of A.P. are positive integers,

but here n comes as a rational number/decimal point.

Thus,

0 can not be the term of given A.P.

Hope it helps you.

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