Question

The armature current of a DC motor is 10 µA with a back emf of 50 V. The applied voltage to the motor is 100 V. Calculate the armature resistance in kilo ohms and also explains Mutual Induction

Answer 1

It's right answer is 5 k ohmz

Answer 2

Given:

$Current, I = 10\mu A = 10\times 10^{-6} \\Back EMF = 50V\\Voltage, V = 100V$

Find: We have to calculate the armature resistance and explains the mutual induction

Step by Step Solution:

We have the expression to calculate the armature resistance,

Back EMF = Applied voltage potential drop across armature coil

$50 = 100 - 10\times 10^{-6}\times R \\-50 = -10^{-5} \times R\\\\R = \dfrac{50}{10^{-5} }\\\\R = 50\times 10^{5}\\\\R = 5\times 10^{6}$

here, the armature resistance is 5000kilo ohm.

Mutual Induction

The term, Mutual Inductance is that the basic operating principal of the transformer, motors, generators and the other electrical component that interacts with another magnetic flux. Then we will define mutual induction because the current flowing in one coil that induces a voltage in an adjacent coil.