Question

the armature of 2 pole 200v and wave wound dc machine has 400 conductors and runs at 300 rpm calculate machine flux per pole​

Answer 1

Answer:

this photo are took for your refrence

Answer 2

Given:

2p = 2

E = 200V

Z = 400 conductors

N = 300 r.p.m

2a = 2

To Find:

The machine flux per pole.

Solution:

E = $\frac{2p}{2a}$ . $\frac{Z}{60} .$ (p).N

200 = $\frac{2}{2}$ .$\frac{400}{6}$.p. 300

p = 0.1 weber

Therefore, the machine flux per pole is 0.1 weber.