Question

The armature of a demonstrator
generator consists of a flat square coil of
side 2 cm and 400 turns. The coil rotates
in a magnetic field of 0.6 T. Calculate the
angular speed so that a maximum emf
of 4.8 V is generated.​

Answer 1

41.25 rad/s is the angular speed with a maximum emf of 4.8 V

Explanation:

Given that,

S = 2

n = 400

B = 0.6 T

ω = ?

ε   = 4.8 V

To find,

ε$_{max}$ = N$A_{o}$Bω

ω = ε$_{max}$/N$A_{o}$B

= 4.8/[400 * 4.8 * 10^-4(0.6)]

= 41.25 rad/s

Learn more: Angular speed

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