the armature of a generator of resistance 1 ohm is rotated at its rated speed and produces 125 V without load and 115 V with full load. the current in armature coil is?
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Answer: 10 A
Explanation:
Given data:
The resistance of the armature of a generator, R = 1 ohm
The armature is rotating at its rated speed and produces, E = 125 V without load
Now, with full load the rate of rotation of the armature reduces and thereby the back emf becomes, Eback = 115V
To find: the current “i” in the armature coil
Now, By applying the KVL in the loop given in the figure attached below,
-E + Eback + (i * R) = 0
Rearranging the eq.,
⇒ i = [E - Eback] / R
Substituting the given values ,
⇒ i = [125 – 115] / 1
⇒ i = 10 A
Thus, the current in the armature coil is 10 A.
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