Math, asked by gkk393163, 8 months ago

The arrival rate of customers at a reservation center follows Poisson distribution with a mean of 55 per hour. The service rate of the counter .clerk also follows Poisson distribution with a mean of 65 per hour, (i) What is the probability of having 0 customer in the system? (ii) What is the probability of having 6 customers in the system

Answers

Answered by amitnrw
0

Given :  The arrival rate of customers at a reservation center follows Poisson distribution with a mean of 55 per hour. The service rate of the counter .clerk also follows Poisson distribution with a mean of 65 per hour,

To find  :  What is the probability of having 0 customer in the system? (ii) What is the probability of having 6 customers in the system

Solution:

P(x)  = λˣ  e^(-λ) / x!

Mean arrival rate of customers  λa = 55

Mean service rate of the counter  λs  = 65

probability of having 0 customer in the system

= 0 customer arrival   +  0 Service   -   ( 0 customer arrival  * 0 Service)

 55⁰  e⁻⁵⁵ / 0!   +  65⁰  e⁻⁶⁵/ 0!   -    55⁰   e⁻⁵⁵ / 0!   x  65⁰   e⁻⁶⁵  / 0!

=  e⁻⁵⁵ +  e⁻⁶⁵ -  e⁻⁵⁵e⁻⁶⁵

=  e⁻⁵⁵ +  e⁻⁶⁵ -  e⁻¹²⁰

probability of having 6 customers in the system

= (6 service)  * ( 6 or more than 6 arriving customers )  + ( 6 Customer arrival) (Service 6 or more than 6 )  - ( 6 customer arrival  * 6 Service)

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